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Integrating Term by Term


 theorem52

.The function f(z) defined by the power series is continuous on C, so the integrals in (1) are well-defined. We need to show that
 equation75

Since C lies inside the circle of convergence, the series converges uniformly on C to f(z). For any tex2html_wrap_inline139, there is an tex2html_wrap_inline141 so that, for all z on C,
displaymath122

By the triangle inequality for integrals and the above inequalities, for tex2html_wrap_inline147
displaymath123

Since tex2html_wrap_inline139 is arbitrary, the limit in (2) is zero.


Taina Malvela
Mon Aug 24 16:00:12 EEST 1998